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Tuesday, August 22, 2006

Lesson 8.3
Tuesday, August 22, 2006
Today, we learned to write and evaluate logarithmic (aka log) functions.
We also learned how to graph the log functions.
Possible warm-up quiz beginning of class Wednesday on 8.1 - 8.3...

BE PREPARED OR B^2
Mrs. S

posted by Mrs. S. at 8:10 AM

4 Comments:

  • Today's Scribes are:
    1st block--Clint Lester
    4th block--Josh Stidham

    By Blogger Mrs. S., at 8:21 AM  

  • Hey Josh Stidham,
    I neglected to tell you during 4th block that you are today's scribe. If you are online tonite, please summarize lesson 8.3 for us.
    Mrs. S

    By Blogger Mrs. S., at 2:59 PM  

  • I guess since this was the last blog posted, i put the lesson in this one... sorry, if it wasn't the right one to put it in...
    ------------------------
    Chapter 8
    Lesson 4 - Properties of Logarithmic Functions


    --The product rule says:
    log(base of)2 4 + log(base of)2 8 = log(base of)2 34

    --The quotient rule says:
    log(base of)3 27 - log(base of)3 9 =log(base of)3 3=1. If you ever have the same base and the same number, it will always equal one because a number divided by itself... is always one. (:

    --The power rule says:
    log(base of)2 X cubed = 3log(base of)2 X. The power of always goes to the front of the log. I.E. -A "BIRD" WILL FLY DOWN TO A LOG. (:

    To expand logxy you just have to find out what was added to get that product... so, logxy = log x + log y. simple. (:

    SUM:
    log(base of)3 20 as a sum would be:
    log(base of) 20=
    log(base of) (4)(5) =
    log(base of)3 4 + log(base of)3 5.


    DIFFERENCE:
    log(base of)3 20 as a difference would be:
    log(base of)3 20=
    log(base of)3 40/2=
    log(base of)3 40 - log(base of)3 2

    SIMPLE LOG:
    3 log 4 + log 5=
    log(base of)4 cubed + log 5=
    log(4cubed)(5) -->4 cubed=64
    =log320

    Another example of a Simple Log:

    3 log(base of)2 7 - log(base of)4 6=
    log(base of)2 7cubed - log(base of)4 6

    Other examples of "expansions" ::

    log(base of)5 (x/y)
    log(base of)5 X - log(base of)5 Y
    -----------
    log 3x to the 4th power
    log 3 + log x to the 4th
    log 3 + 4 log x
    -----------
    log (y/3)squared
    2log(y/3)
    2[log Ycubed - log 3)

    Sorry if all of the base of and cubed.. etc.. were confusing, i didn't know how else to explain it. Hope it helped though. Sorry it was so late also... I got home late.

    By Blogger Kristina, at 10:18 PM  

  • To "get" the product rule problems, you just multiply the NUMBERS together, not the bases.

    To "get" the quotient rule problems, divide the numbers.

    To "get" the power rule problems, let the "bird" ((aka:: power)) fly down in front of the "log". ;)
    --------


    ****edit to the SUM part


    SUM:
    log(base of)3 20 as a sum would be:
    log(base of)3 20=
    log(base of)3 (4)(5) =
    log(base of)3 4 + log(base of)3 5.

    By Blogger Kristina, at 10:24 PM  

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